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[AtCoder]ABC-212|B - Weak Password
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提出結果
def getString():
return input()
def gap(n, m):
return (10 if n == 0 else n) - m
def main():
x = list(map(int, getString()))
y = [gap(x[i + 1], x[i]) for i in range(len(x) - 1)]
r = 'Strong'
if len(set(x)) == 1:
r = 'Weak'
elif len(set(y)) == 1 and sum(y) == 3:
r = 'Weak'
print(r)
if __name__ == "__main__":
main()
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